For each one of the four cations, write balanced equations for each reaction tha
ID: 1073321 • Letter: F
Question
For each one of the four cations, write balanced equations for each reaction that occurs. Since the "active ingredient" in combo is NH_4OH, a reaction with combo is the same reaction as with NH_4OH. It does not have to be written twice. For convenience you may use either NH_3 or NH_4OH for ammonia. Potassium is a spectator ion. It may be ignored in the equations. If no complex forms, write NA at the last requested equation. Reactions involving the maganesium ion Mg^+2 with NaOH: small amount: excess: Mg^+2 with NH_4OH (NH_3): small amount: excess: Mg^+2 with K_4 [Fe(CN)_6]: Mg^+2 hydroxide precipitate and HNO_3: Mg^+2 complex ion and HNO_3: Reactions involving the iron (III) ion Fe^+3 with NaOH: small amount: excess: Fe^+3 with NH_4OH (NH_3): small amount: excess: Fr^+3 with K_4 [Fe(CN)_6]: Fe^+3 hydroxide precipitate and HNO_3: Fe^+3 complex ion and HNO_3: Reactions involving the zinc ion Zn^+2 with NaOH: small amount: excess: Zn^+2 with NH_4OH (NH_3) small amount: excess: Zn^+2 with K_4[Fe(CN)_6]: Zn^+2 hydroxide precipitate and HNO_3: Zn^+2 complex ion and HNO_3: Reactions involving the aluminum ion Al^+3 with NaOH: small amount: excess: Al^+3 with NH_4OH (NH_3): small amount: excess: Al^+3 with K_4[Fe(CN)_6]: Al^+3 hydroxide precipitate and HNO_3: Al^+3 complex ion and HNO_3:Explanation / Answer
Reactions
With Mg2+
Mg2+ + 2NaOH --> Mg(OH)2 (ppt) + 2Na+ (both in small and excess amount)
Mg2+ + 2NH4OH --> Mg(OH)2 (ppt) + 2NH4+ (both in small and excess amount)
Mg2+ + K4Fe(CN)6 ---> Mg2Fe(CN)6 (ppt)
Mg(OH)2 + 2HNO3 ---> Mg(NO3)2 + 2H2O
No reaction
With Fe3+
Fe3+ + 3OH- --> Fe(OH)3 (ppt) (both in small and excess amount)
Fe3+ + 3NH4OH --> Fe(OH)3 (ppt) (both in small and excess amount)
Fe3+ + K4Fe(CN)6 --> KFe(CN)6 (ppt)
Fe(OH)3 + 3HNO3 --> Fe(NO3)3 + 3H2O
Fe[(CN)6]3- + 3HNO3 ---> Fe(NO3)3 + 3HCN + 3CN-
With Zn2+
Zn2+ + 2OH- ---> Zn(OH)2 (small)
Zn2+ + 2OH- ---> Zn(OH)4^2- (excess)
Zn2+ + 2NH3 --> Zn(NH3)2^2+ (small)
Zn2+ + 2NH3 --> Zn(NH3)4^2+ (excess)
Zn2+ + K4Fe(CN)6 ---> Zn2Fe(CN)6 (ppt)
Zn(OH)2 + 2HNO3 --> Zn(NO3)2 + 2H2O
Zn(OH)4^2- + 2HNO3 --> Zn(NO3)2 + 2H2O + 2OH-
With Al3+
Al3+ + 3OH- --> Al(OH)3 (ppt) (small)
Al3+ + 4OH- --> Al(OH)4^- (excess)
Al3+ + 3NH4OH --> Al(OH)3 (ppt) + 3NH4+ (small)
Al3+ + 4NH4OH --> Al(OH)4^- + 4NH4+ (excess)
No reaction
Al(OH)4^- + 4HNO3 --> Al(NO3)3 + 4H2O
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