You prepare NaOH solution by dissolving 1.7650g of pure BaOH in sufficient water

Question

You prepare NaOH solution by dissolving 1.7650g of pure BaOH in sufficient water to make 400mLs of solution. What is the molarity of the sodium hydroxide solution?
A) if you use 22.60mL of the base to neutralize 30.0mL of the sulfuric acid, what is the molarity of the sulfuric acid? You prepare NaOH solution by dissolving 1.7650g of pure BaOH in sufficient water to make 400mLs of solution. What is the molarity of the sodium hydroxide solution?
A) if you use 22.60mL of the base to neutralize 30.0mL of the sulfuric acid, what is the molarity of the sulfuric acid?
A) if you use 22.60mL of the base to neutralize 30.0mL of the sulfuric acid, what is the molarity of the sulfuric acid?

Explanation / Answer

Weight of the NaOH = 1.765 gm

Molarity of the NaOH solution = 1.765 x 1000 /400 x40 = 0.1103 M .

Moles of the NaOH to be taken = 20 x 0.1103 /1000 = 0.002206

   Moles of the H2SO4 that needed to be neutralized = 0.00206 /2 = 0.001103 M

Molarity of the H2SO4 = 0.001103 x 1000 / 30 = 0.03676 M

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