Enter your answer in the provided box. Some commercial drain cleaners contain a

Question

Enter your answer in the provided box. Some commercial drain cleaners contain a mixture of sodium hydroxide and aluminum powder. When the mixture is poured down a clogged drain, the following reaction occurs: 2NaoH(aq) +2Al(s) 6H20 2NaAl(OH)4(aq) 3H20g) The heat generated in this reaction helps melt away obstructions such as grease, and the hydrogen gas released stirs up the solids clogging the drain. Calculate the volume of H2 formed at 27.5°C and 1.00 atm if 4.17 g of Al is treated with an excess of NaoH.

Explanation / Answer

molar mass of Al = 26.981539 gm/mol then 2 mole of Al = 53.963078 gm

molar mass of H2 = 2.01 gm/mol then 3 mole of H2 = 6.03 gm

According to reaction 2 mole Al reacted produce 3 mole of H2 that mean when 53.963078 gm of Al reacted produce 6.03 gm of H2 then 4.17 gm Al produce = 4.17 X 6.03 / 53.963078 = 0.4659686 gm of H2 formed

molar mass of H2 = 2.01 gm/mol then  0.4659686 gm of H2 =  0.4659686 /2.01 = 0.231825175 mole of H2

Use ideal gas equation to calculate volume of H2

We know that PV = nRT

V = nRT/P

n = 0.231825175 mole,

T = 27.50C = 27.5 + 273.15 = 300.65K,

P= 1 atm,

R = 0.08205 L atm mol-1 K-1 ( R = gas constant)

V = ?

Substitute these value in above equation.

V =0.231825175 X 0.08205 X 300.65 / 1 = 5.72 L

volume of H2 produced = 5.72 L

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