For a given reduced/oxidized molecular pair (X – /X), a negative reducing potent

Question

For a given reduced/oxidized molecular pair (X–/X), a negative reducing potential suggests that the X– has a higher affinity for the electrons than X does. X has a higher affinity for electrons than H2 does. X– has a lower affinity for the electrons than X does. X has a lower affinity for electrons than H2 does. For a given reduced/oxidized molecular pair (X–/X), a negative reducing potential suggests that the X– has a higher affinity for the electrons than X does. X has a higher affinity for electrons than H2 does. X– has a lower affinity for the electrons than X does. X has a lower affinity for electrons than H2 does.

Explanation / Answer

if the potential is negative... this implies that

X has a lower affinity for electrons than H2 does.

Since H2 will have a higher potential to reduce, that is

2H+ + 2e- = H2(g) will form

and

2X(s) = 2X- + 2e- is likely to form, so it has lower affinity

X has a lower affinity for electrons than H2 does.

Since H2 will have a higher potential to reduce, that is

2H+ + 2e- = H2(g) will form

and

2X(s) = 2X- + 2e- is likely to form, so it has lower affinity

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