Solid magnesium hydroxide is placed in water and an equilibrium forms with its i

Question

Solid magnesium hydroxide is placed in water and an equilibrium forms with its ions. Write the equilibrium reaction. If a strong add, such as HCI, is added to the equilibrium mixture, how is the equilibrium affected and what experimental observations would be made? If next, a strong base such as NaOH is added to the newly formed equilibrium mixture, how would the equilibrium be affected and what experimental observations would be made? If the desire was to eliminate virtually all the Mg^2+ ions from solution, how could this be accomplished?

Explanation / Answer

Q1

a)

Mg(OH)2(s) + H2O(l) = ions

the equilibirum reaction is given by solubility of aqeuous ions + soldi

Mg(OH)2(s) <-> Mg+2(aq) + 2OH-(aq)

b)

H+ addition will form:

OH- + H+ = H2O(l)

then, OH- concnetration decreases, this forces shift of equilbrium towards more ion in aqueous solution, therefore the solid will increase solubility

c)

Additiono f OH- will increase OH- ions in solution

this will favour more SOLID Mg(OH)2 formation, since the shift is now toward reactants (solids)

d)

Add Plenty of OH- ions in solution, i.e. pH must be pretty high about 13-14

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