The energy required to convert a single atom of page 6 of 19 determined from the

Question

The energy required to convert a single atom of page 6 of 19 determined from the energy hydrogen to a gaseous H+ ion can be of the photon required to excite the electron from the lowest energy state to the state with the quantum number n infinity (where E 0). Based on the Rydberg-Balmer equation below for a hydrogen atom, what is the energy required to ionize a MOLE of hydrogen atoms? R(1/m 1/n and R 2.18x10 J (a) 2.18x10 J (c) 1.31x106 J (d) 5.3x10 J (e) 7.5x104 J 9. A chemical engineer in a pilot plant produces the plasticizer dibutyl phthalate (c16Hmo. MW 278.4) by reacting 100.0 kg of butanol (C4HioO, MW 74.14) with 125.0 phthalic acid (CsHeo, MW 166.1). he balanced equation is below. The engineer recovers 175.3 kg of dibutyl phthalate as the actual yield. What is the percent yield in this reaction? csHooa 2 C4H10o C16H2204 2 Hoo (a) 0.8314% (b) 83.14% (c) 77.92% (d) 92.70% (e) 108.0% o. The electron configuration of Ti and the number of unpaired electrons are (a) [Ar] 4s2 3d2, 4 unpaired electrons (b) [Ar] 4s2 4p 2 unpaired electrons (c) [Ar] 3d4, 4 unpaired electrons (d) [Arl 4s2 3d2, 0 unpaired electrons (e) [Ar 4s2 3d2, 2 unpaired electrons The enthalpy for combustion of octane (CsHis, balanced equation below) is -11020 kJ/mol. Given that AHr of Co20g) is -393.5 kJ/mol and AHP of Hizo(ly is -285.8 kJImol, calculate the enthalpy of formation (AH of one mole of octane. (a) +22040 kJ

Explanation / Answer

8)
m = infinity
n= 1

for 1 atom:
E = -R*(1/m^2 - 1/n^2)
E = - 2.18*10^-18 * (0 - 1)
= 2.18*10^-18 J

for 1 mol, there are 6.022*10^23 atom

E for 1 mol = 2.18*10^-18 * 6.022*10^23 = 1.31*10^6 J

Answer: 1.31*10^6 J

it is taking time. So I can answer only 1 question at a time.

I am allowed to answer only 1 question at a time

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.