2. (10 points) The apparatus shown consists of three bulbs, connected stopcocks.

Question

2. (10 points) The apparatus shown consists of three bulbs, connected stopcocks. When the bulbs are first filled, the by Bulb A room temperature is At this temperature: contains CO2 at a pressure of 2.13 and has a volume of 1.5 L. Bulb empty and has a volume of 1.0 Bulb C contains Ar at a pressure of 1.15 atm and has a volume of 2.00 L. On a day when the temperature is 0°C, t valves are is the total pressure inside the system after the stopcocks are opened and the gases freely mix? Assume the lines connecting the bulbs have zero volume

Explanation / Answer

Initial temperature of system = 25 0C = 298.15 Kelvin

Volume of bulb A = 1.5 L ,Pressure = 2.13 atm

so moles of CO2 = PV / RT

R = gas constant = 0.0821 L atm / Mol K

moles of CO2 = 2.13 X 1.5 / 0.0821 X 298.15 = 0.131 moles

volume of bulb B= 1 L

Volume of Bulb C= 2 L , Pressure = 1.15 atm

so moles of argon = PV / RT

moles of argon = 1.15 X 2 / 0.0821 X 298.15 = 0.094 moles

Total moles = 0.131 +0.094 moles = 0.225 moles

After the valves were opened

Total volume = 1.5 + 1 + 2 = 4.5 L

Final temperature = 0 0C = 273.15 K

Moles = 0.225 moles

Pressure = ?

PV = nRT

Pressure = nRT / V = 0.225 x 0.0821 X 273.15 / 4.5 = 1.121 atm

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