63. How many orbitals in the d sublevel? are 64. As you look from left to right
ID: 1072642 • Letter: 6
Question
63. How many orbitals in the d sublevel? are 64. As you look from left to right on the periodic table, what happens to the electronegativity 65. You have the following information about the atomic mass of an element. Find the average atomic mass. Mass actual atomic mass percent abundance relative abundance Zn 64 63.929 48.6 Zn66 65.926 27.9 67 66.927 4.1 Zn 67.924 18.8 70 Zn 69.925 0.6 66. If the atomic number for an element is 84 and the mass number is 209, how many valence electrons will it have? 68 70 8.98 x 1023 nm 3.928 x 10 ll nm 71. 3225.50 137 1.0mL. many eleetioExplanation / Answer
63) there are 5 orbital in d subshell
because d subshell have l = 2 and
Ml = -2, -1, 0, +1, +2
64) From left to right electronegativity increases in periodic table
because left side element to right side element sucessive 1 electron increses and therefore tendacy to lose electron for complete octate decreases from left to right therefore right side element have more tency to take electron for complete octate than left side element therefore right side element are more electronegative than left side element and trend is From left to right electronegativity increases in periodic table
65)Avarage atomic mass Zn = [( mass of Zn - 64 X % abundace of Zn - 64 ) + ( mass of Zn - 66 X % abundace of Zn - 66 ) +( mass of Zn - 67 X % abundace of Zn - 67 ) + ( mass of Zn - 68 X % abundace of Zn - 68 ) + ( mass of Zn - 70 X % abundace of Zn - 70 )] 100
substitute value
[(63.929 X 48.6) +(65.926 X 27.9) + (66.927 X 4.1) + (67.924 X 18.8 ) + (69.925 X 0.6)]/100
= [(3106.8522) + (1839.3354)+( 274.4007) + (1276.9712) + (41.955)]/100
= 65.395145
Actual atomic mass of Zn = 65.395145 u
66) Atomic number of element is 84 thus it contain total 84 electron
electronic configuration of element is [Xe]4f145d106s26p4
thus, outer shell contain 6 electron ie. there is 6 valence electron.
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