Answer the questions below with the help of the following information. The heat

Question

Answer the questions below with the help of the following information. The heat of fusion of ice 3.4 times 10^2 J/g The heat of vaporization of water 2.3 times 10^3 J/g Specific heat of water = 4.184 J/g degree C a) How much heat must be supplied to melt 45 g of ice? b) How much heat must be supplied to raise the temperature of 45 g of water from 0 degree C to 100 degree C? c) How much heat must be supplied to change 45 g of water at 100 degree C to steam? d) How much heat must be supplied to change 45 of ice at 0 degree to steam at 100 degree C?

Explanation / Answer

Q14

For melting 45 g of ice:

mol = mass/MW = 45/18 = 2.5

Q = n*LHeat of melting

Q = 2.5*3.4*10^2 = 850 J

b)

from 0 to 100

Q = m*C*(Tf-Ti)

Q = 45*4.184*(100-0) = 18828 J

c)

steam:

Q = n*LLheat vap

Q = 2.5*2.3*10^3 = 5750 J

d)

total heat

Qtotal = Qa + Qb+Qc = 850+18828+5750 = 25,428 J

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