1. Aluminum reacts with oxygen to produce aluminum oxide. 4 Al(s) 3020g) 2 Alzo,

Question

1. Aluminum reacts with oxygen to produce aluminum oxide. 4 Al(s) 3020g) 2 Alzo, (s) If 12.0 moles of Al react with excess O., how many moles of Al,O, can be formed? (5 points) 2.What is the pH of 0.51 M HCl(aq)? (5 points) 3. An experiment in your laboratory requires 500 ml of 0.02 M solution of Na,COs. You are given solid Na,CO, distilled water, and a 500-ml volumetric flask. Describe how to prepare the required solution. (10 points) Chapter 5 boiling point of 80.1 °C. How much energy in the form of heat is required to vaporize 102 g benzene at its boiling point? (10 points) Nitrogen monoxide, a gas recently found to be involved in a wide range of biological processes, reacts with oxygen to give brown NO2 gas. 2 NO(g) Oz(g) 2 NO, (g) AH 114.1 kJ/mol-rxn. Is this reaction endothermic or exothermic? What is the enthalpy change if 1.25g of NOis converted completely to NO,? (10 points) Chapter 6 6, If an FM radio station broadcasts at 92.1 MHz, what is the wavelength of this radiation? (6 points) 1.Excited hydrogen atoms emit light in the infrared at 1.87 x 10 m. What is the energy of a single photon with this wavelength? (6 points) s. How many orbitals have the following set of quantum numbers: n 6,1 3, m 9 What shell contains a total of 16 orbitals? (3 points) lo Which n shell is the lowest that may contain d-orbitals. (3 points) Chapter 7 How many electrons can be described by the following quantum numbers: n 3,1 1, m 0, m 1/2? (3 points) 12 Write the electron configurations for P and Cl using both spdf notation ad orbital box diagrams. Describe the relationship between each atom's electron configuration and its position in the periodic table. (16 points)

Explanation / Answer

Q1.

n = 12 mol of Al, excess O2, then

ratio is 4 mol of Al per 2 mol of Al2O3

then

12 mol = 2/4*12 = 6 mol of Al2O3 are expected

Q2

for pH

we need to know [H+] concentration

since

pH = -log([H+])

assume [H+] = [HCl] since ratio is 1:1

pH = -log(0.51) = 0.29242

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