The gas constant is 8.31446 J middot mol^-1 middot K^-1. (1 J = 1 Pa middot m^3)

Question

The gas constant is 8.31446 J middot mol^-1 middot K^-1. (1 J = 1 Pa middot m^3) At a temperature of 54 degree C and a pressure of 109816 Pa, a certain compound is in the gaseous state. Under these conditions a volume of 0.320 L of this compound weight 0.5697 g. The molar mass (molecular weight) of this compound is: 5.3 g middot mol^-1 7.3 g middot mol^-1 14.1 g middot mol^-1 44.1 g middot mol^-1 48.4 g middot mol^-1 53.0 g middot mol^-1 73.6 g middot mol^-1 134.8 g middot mol^-1 None of the above; the correct molar mass is g middot mol^-1

Explanation / Answer

from idealgas equation

PV = nRT

PV = W/mWT*RT

p = pressure of gas= 109816 pa = 1.084 atm

V = volume of gas = 0.32 L

W = weight of gas = 0.5697 g

Mwt = molarmass of gas = ?

R= gas constant = 8.314 j.mol-1.k-1 = 0.0821 l.atm.k-1.mol-1

T = temperature of gas = 54+273.15 = 327.15 k

(1.084*0.32) = (0.5697/Mwt)*0.0821*327.15

Mwt = molarmass of gas = 44.11 g/mol

answer: d

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