How does this change in stoichiometric coefficients affect the equilibrium const

Question

How does this change in stoichiometric coefficients affect the equilibrium constant expression? CH_4(g) + 2H_2O(g) CO_2(g) + 4H_2(g) K_p = X 2CH_4(g) + 4H_2O(g) 2CO_2(g) + 8H_2(g) K_p = ? The value of K_p is X. 2X. 4X. X^2. A chemical reaction is performed at 200 K and at 400 K. The reaction has activation energy of 50.0 kJ middot mol^-1. At 400 K the rate of reaction is the same as the rate at 200 K. over 3 million times the rate at 200 K. approximately double the rate at 200 K: approximately 200 times the rate at 200 K.

Explanation / Answer

32. if equation multiplied with 2 , so that Kp = x^2

answerer : D

33. ln(k2/k1) = DHrxn/R[1/T1 - 1/T2]

              = 50*10^3/8.314*((1/200)-(1/400))

        ln(k2/k1) = 15.035

    k2/k1 = 3.38*10^6

so that , k2 = 3.38*10^6*k1

answer: B

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