(1) Exercise 13.93 A 10.0 mL sample of an unknown H3PO4 solution requires 102 mL
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Question
(1) Exercise 13.93
A 10.0 mL sample of an unknown H3PO4 solution requires 102 mL of 0.150 M KOH to completely react with the H3PO4.
What was the concentration of the unknown H3PO4 solution?
H3PO4(aq)+3KOH(aq)3H2O(l)+K3PO4(aq)
(2) Exercise 12.67
What kinds of intermolecular forces are present in a mixture of carbon dioxide and methane?
d. dipole-dipole
(3) Exercise 12.68
What kinds of intermolecular forces are present in a mixture of nitrogen oxide and hydrogen chloride?
(4) Exercise 12.106
Water does not easily remove grease from dirty hands because grease is nonpolar and water is polar; therefore they are immiscible. The addition of soap, however, results in the removal of the grease .
Examine the structure of soap shown here (Figure 1) and explain how soap works.
d. The soap molecule is rather large and thus the dispersion forces between the soap molecules are strong enough to remove grease.
a. dispersion and dipole-dipole b. dispersion, dipole-dipole, and hydrogen bonding c. dispersiond. dipole-dipole
(3) Exercise 12.68
What kinds of intermolecular forces are present in a mixture of nitrogen oxide and hydrogen chloride?
dispersion and dipole-dipole ion-dipole and dipole-dipole dispersion dipole-dipole, ion-dipole, and hydrogen bonding(4) Exercise 12.106
Water does not easily remove grease from dirty hands because grease is nonpolar and water is polar; therefore they are immiscible. The addition of soap, however, results in the removal of the grease .
Examine the structure of soap shown here (Figure 1) and explain how soap works.
a. The soap molecules, which are almost nonpolar, can be polarized when mixed with water. The grease then dissolves in the polarized soap molecules. b. When soap is mixed with water, it weakens the interactions between the water molecules, therefore, alowing grease to dissolve in water. c. One end of the soap molecule is polar, which likes to be in water, and the other end is nonpolar, which can dissolve the grease.d. The soap molecule is rather large and thus the dispersion forces between the soap molecules are strong enough to remove grease.
CH3(CH2)16C-O Nat Polar head Nonpolar tail Sodium stearate a soapExplanation / Answer
1. H3PO4(aq)+3KOH(aq)3H2O(l)+K3PO4(aq)
M1V1/n1 = M2V2/n2
(M1*10/1) = (102*0.15/3)
M1 = molarity of H3PO4 = 0.51 M
2. CO2 - nonpolar , CH4 - nonpolar
ANSWER: c. dispersion
3. NO2 , HCl
ANSWER: dispersion and dipole-dipole
4. ANSWER: c. One end of the soap molecule is polar, which likes to be in water, and the other end is nonpolar, which can dissolve the grease.
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