Zinc reacts with HCl according to the equation: Zn + 2HCl rightarrow ZnCl_2 + H_

Question

Zinc reacts with HCl according to the equation: Zn + 2HCl rightarrow ZnCl_2 + H_2 Suppose we weighed out 0.148 Zn and added excess HCl. What volume (in mL) of H_2 gas would be obtained at STP? 101 ml 0.00226 ml. 22.4 mL 50.7 ml. An unknown hydrocarbon gave g of CO_2 and 0.02523 g of H_2O on combustion. What the empirical formula of this unknown hydrocarbon? CH CH_3 C_2H CH_2 There are two naturally occurring isotopes of Li^6Li has an isotopic mass of 6.01512 amu and^7Li has an isotopic mass of 7.01600 amu. What the percent abundance of^7U? 1.00% 6.52% 7.59% 92.4%

Explanation / Answer

82)
number of moles of Zn = mass/molar mass
= 0.148 g / 65.4 g/mol
= 2.263*10^-3 mol

from given chemical reaction,
1 mol of Zn forms 1 mol of H2

so,
moles of H2 formed = 2.263*10^-3 mol

molar volume = 22.4 L /mol

so,
volume = 2.263*10^-3 mol * 22.4 L/mol
=5.07*10^-2 L
= 50.7 mL

Answer: 50.7 mL

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