For the reaction 2n(s) + 2HCl (aq) = ZnCl_2(aq) + H_2(g), assume 1.0 mole of eac

Question

For the reaction 2n(s) + 2HCl (aq) = ZnCl_2(aq) + H_2(g), assume 1.0 mole of each substance is present initially and the reaction proceeds to completion in the left to right direction. The limiting reagent is: a) Zn(s) b) HCl (aq) c) ZnCl_2(aq) d) H_2(g) In question 1, the extent of raction would be: a)0.5 b) 1.0 c)-0.5 d)-1.0 Considering the formula delta G = delta G_0 + RT ln Q. Q = the equilibrium constant K when delta G is: a) larger than delta G_0 b) smaller than delta G_0 c) equal to delta G_0 d) zero Consider the reaction CaCo_2(g) + 2H^+ + Ca^+2(aq) + CO_2(g) + H_2O(l). The proper equilibrium constant expression for this reaction is: a) a(ca^+2)^2 p/p_0(CO_2) p/p_0(H_2O)/a(CaCO_2)a(H^+)^2 b) a(Ca^+2)^2 p/p_0(Co_2)a(H_2O)/a(CaCO_3)a(H^+)^2 c) a(Ca^+2)^2 p/p_0 (CO_2) p/p_0(H_2O)/a(H^+)^2 d) a(Ca^+2) p/p_0 (Co_2)/a(H^+)^2) To find the equilibrium constant k at 500 k if k at 298 k is known, the best formula to use is: a) delta G_0 =() RT ln k b) ln (K_2/K_1) = delta H/R(1/T_1-1/T_2)c) ln k=V/RT (p-1) d) k = Y m(M/1000)

Explanation / Answer

Question1

Now here se have the following reaction

Zn + 2 HCl = ZnCl2 + H2

Initial moles 1 1 0 0

Final moles 0.5 0 0.5 0.5

Now we have seen here that coefficient of HCl is 2 whereas that of Zn is 1 , SO 1 mole of Zn react with 2 mole of HCl. Hence 0.5 moles of Zn react with 1 mole of HCl and further cannot react as we have just 1 mole of HCl . So here HCl act as limiting reagant.

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