Data for radioisotope experiment: Answer the following questions according to th
ID: 1067233 • Letter: D
Question
Data for radioisotope experiment: Answer the following questions according to the collected data above: Do you think its necessary to subtract the "no source" and "air/no shielding" value from your other measurements? Why or why not? Is there a material (paper, foil, gelatin) that seemed to stop the most radiation, regardless of the type of radiation? Speculate on why this might be. Is there a type of radiation (alpha, beta, gamma) that seems easiest to stop, based on your results? Why might this be, in terms of the physical properties of that type of radiation?Explanation / Answer
1.
No source reading of 54 for air (no shielding) should be substracted from the readings under the column No shielding (air). This will account for background noise. But when we use shielding (paper, aluminum foil or gelatin sheet), the value 54 drops to 0. Hence, there is no need to substract this value from readings for shielding.
2.
There is no material that seemed to stop the most radiation. Thus, we can see that significant amount of beta and gamma rays pass through shielding.
3.
No source reading of 54 for air (no shielding) should be subtracted from the readings under the column No shielding (air). This will account for background noise. But when we use shielding (paper, aluminum foil or gelatin sheet), the value 54 drops to 0. Hence, there is no need to subtract this value from readings for shielding.
There is no material that seemed to stop the most radiation. Thus, we can see that significant amount of beta and gamma rays pass through shielding.
Alpha particles are easiest to stop as more than 85% them are shielded with paper, aluminum foil or gelatin sheet.
Alpha particles have maximum mass among the given radiation. Hence, they are easy to stop.
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