Please answer all page Which of the following is true about the kinetic molecula

Question

Please answer all page Which of the following is true about the kinetic molecular theory? The volume of a gas particle is considered to be small-about 0 10 mL. Pressure is due to the collisions of the gas particles with the walls of the container. Gas particles repel each other, but do not attract one another. Adding an ideal gas to be closed container will cause an increase in temperature. Benzene is a starting material in the synthesis of nylon fibers and polystyrene. If 26.7 kJ of energy is absorbed by a 225 g sample of benzene initially at 20 Degree C, what will its final temperature be? The specific heat capacity of benzene = 1.74 1/g Degree C -22.7 Degree C 36.7 Degree C 42.7 Degree C 62.7 Degree C A system delivers 1275 J of heat while the surroundings perform 855 J of work. Calculate the change in the internal energy, Delta E, of the system. -2130 J -420 J 420 J 2130 J For which of the following reactions will Delta H be approximately (or exactly) equal to Delta E? H_2(g) + Br_2(g) rightarrow 2 HBr(g) H_2O(l) rightarrow H_2O(g) CaCO_3(s) rightarrow CaO(s) + CO_2(g) CH_4(g) + 2 O_2(g) rightarrow CO_2(g) + 2 H_2O(l) Use Hess's Law to calculate the enthalpy change for the reaction Mn(s) + O_2(g) rightarrow MnO_2(s) from the following data: 2 MnO_2(s) rightarrow 2 MnO(s) + O_2(g) Delta H = 264 kJ 2 MnO_2(s) + Mn(s) rightarrow 2 MnO(s) Delta H = -240 kJ -504 kJ -372 kJ 24 kJ 504 kJ An important step in the synthesis of nitric acid is the conversion of ammonia to nitric oxide. Calculate Delta H Degree for this reaction.4 NH_3(g) + 5 O_2(g) rightarrow 4 NO(g) + 6 H_2O(g) Delta H Degree _r[NH_3(g)] = -45.9 kJ/mol Delta H Degree _r[O_2(g)] = 0.0 kJ/mol Delta H Degree _r[NO(g)] = 90.3 kJ/mol Delta H Degree _r[H_2O(g)] = -241.8 kJ/mol -906.0 kJ -197.4 kJ -105.6 kJ 906.0 kJ

Explanation / Answer

23. The answer would be option-b which is a correct statement of kinetic theory of gases

24. 225 g of sample = 0.225 kg. With specific heat = 1.74 kJ/kgdeg C. Amt of heat added is given by the equation, q=mCpdelta T. Therefore 26.7 = 0.225 * 1.74 * (T - 20) .Therefore T = 88.19 deg C

25. Change in internal enerygy U = q - W = -1275 + 855 = -420 J

26. Change in internal energy and change in enthalpy is almost equal for a reaction with volume change = 0

26. Change in internal energy will be same as change in enthalpy for reactions. It an be seen that only for option A volume wont change with reaction proceedings because it is a single phase reaction with no conversion from gas to liquid

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