Drinking cold water will actually burn a small number of Calories as the water i

Question

Drinking cold water will actually burn a small number of Calories as the water is warmed to body temperature. Consider a person that drinks 1.00 gallon of cold water at 4.0 degree C. How much energy (in food Calories) will the person have to burn, if the cold water must be warmed to their CONSTANT body temperature of 98.6 degree F? 1.00 gallon = 3.785 L Density of water at 4 degree C = 1.00 g/mL 1 food Calorie (with a capital c = 1 kilocalorie (with a lower case c) 1 calorie (with a lower case c) = 4.184 Joules (J)

Explanation / Answer

V = 1 gal of water T = 4°C

T = 98.6°F --> 37 °C (human body temperature)

so..

dT = 37-4 = 33 °C

change to mass of water

1 gal = 3.785 L --> 3.785 kg = 3785 g

Q = m*C*(Tf-Ti)

Q = 3785 *1 * (33) = 124905 calorie

Q = 124905/1000 = 124.905kcalories

Q = 124.905 Calories

On a basis of 2000 calories, this is about6 % but note that 1 gallon is almos 1.5x more than the addvisable 2L of water consumption

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