NEED HELP WITH MY CHEM REVIEW ASAP! A mixture contains 5.0 g each of oxygen gas,

Question

NEED HELP WITH MY CHEM REVIEW ASAP! A mixture contains 5.0 g each of oxygen gas, nitrogen gas, and carbon dioxide. Calculate the volume of this mixture at STP. Calculate the partial pressure of each gas in the mixture.
The answer is: 10.06L, but I need help understanding this. Can this be worked out and explained step-by-step? NEED HELP WITH MY CHEM REVIEW ASAP! A mixture contains 5.0 g each of oxygen gas, nitrogen gas, and carbon dioxide. Calculate the volume of this mixture at STP. Calculate the partial pressure of each gas in the mixture.
The answer is: 10.06L, but I need help understanding this. Can this be worked out and explained step-by-step? NEED HELP WITH MY CHEM REVIEW ASAP!
The answer is: 10.06L, but I need help understanding this. Can this be worked out and explained step-by-step?

Explanation / Answer

number of moles of O2 = mass/molar mass
= 5.0/32
= 0.1563 mol

number of moles of N2 = mass/molar mass
= 5.0/28
= 0.1786 mol

number of moles of CO2 = mass/molar mass
= 5.0/44
= 0.1136 mol

total number of moles,
n = 0.1563 + 0.1786 + 0.1136 = 0.4481 mol

at STP,
P = 1 atm
T = 273 K

use:
P*V = n*R*T
1*V = 0.4481*0.0821*273
V = 10.04 L

Answer: volume of this mixture is 10.04 L

p(O2) = n(O2)*Ptotal / ntotal
= 0.1563*1/0.4481
= 0.3488 atm

p(N2) = n(N2)*Ptotal / ntotal
= 0.1786*1/0.4481
= 0.3986 atm

p(CO2) = n(CO2)*Ptotal / ntotal
= 0.1136*1/0.4481
= 0.2536 atm

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