Calculate the concentration of the standard HCl solution you prepared. Determine

Question

Calculate the concentration of the standard HCl solution you prepared. Determine this concentration for each trial and the average and standard deviation for all three trials.
Part B-Preparation and standardization of an HCl Solution 1. Before you can titrate your saturated Ca(oH)a solutions, you must prepare and standardize a dilute solution of Hcl. With a graduated cylinder measure at least 6 mL of the stock Hcl lution, transfer it to a 125 mL Erlenmeyer, and dilute to approximately 100 mL (the exact volumes at this point in the prep are not important). 2. Rinse and fill the buret with the HCl solution you just prepared. add 5.00 3. obtain about 25 mL of standardized NaoH solution in a beaker. Using a volumetric pipet, flask. 4. mL (the exact volume is important) of standardized NaoH solution into a 50 mL Erlenmeyer and final Add 3 drops of bromothymol blue indicator and titrate with the HCI. Record your initial buret readings to the nearest 0.01 mL. 5. Repeat the standardization procedure twice for a total of three trials. 6. HCI You JusT -Do NOT DISPOSE. However, your flasks and volumetric must be thoroughly cleaned with soap and warm water and rinsed before continuing to the the procedure. Contamination will significantly alter the results in the next part of next section of the lab procedure.

Explanation / Answer

We wish to find its concentration by titration with 0.1000 M NaOH. (M is the notation for the concentration unit called molarity, which is defined as the number of moles of a substance per liter of solution. A mole is equal to 6.022 x 1023molecules.) moles HCL = moles NaOH

For standardization of acid we require to have standardized Base .

Standardization process is necessary for Secondary Standards.

For NaOH and HCl

Molarity = Normality

so We can use this Equation

N1V1=N2V2

Where,

N1= Normality Of HCl=Unknown

V1=Volume of HCl (Burette Reading)=8.43 ml

N2=Normality Of NaOH =0.1N

V2 =Volume of NaOH Used = 5ml

N1=N2V2 / V1

N1=0.1*5/ 8.43

N1=0.0593N

If you have used NaOH that has different concentration you can simply change its value in above equation.

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.