Write the three chemical equations for the three equilibria that describe the fo
ID: 1062777 • Letter: W
Question
Write the three chemical equations for the three equilibria that describe the formation of the three precipitates you listed in the table in question 1. Interestingly, we find that the exact same precipitate forms for a particular metal cation, regardless whether we use NaOH(aq), NH_3(Aq), or Na_2CO_3(aq), as the precipitating reagent. And we name the resulting salt to reflect the anion that is present. That anion is (chemical formulation and charge) or (name) How can we explain the formation of that particular precipitate? Support your answer with chemical equations) showing why this anion is free in the solution. Obtain the Ksp values (solubility product Konstant) for aluminum hydroxide, copper(II) hydroxide, and zinc hydroxide, and write them below. Which of these three hydroxides is most soluble? Least soluble? How do you know?Explanation / Answer
AlCl3(aq) + 3 NaOH(aq) = 3 NaCl(aq) + Al(OH)3(s)
Reaction type: double replacement
Reaction stoichiometry
Compound
Coefficient
Molar Mass
AlCl3(aq)
1
133.3405386
NaOH(aq)
3
39.99710928
NaCl(aq)
3
58.44276928
Al(OH)3(s)
1
78.0035586
CuFe(CN)6
2 Cu(NO3)2(aq) + Fe(CN)6(aq) = Cu2Fe(CN)6(s) + 4 NO3(aq)
Reaction type: double replacement
Reaction stoichiometry
Compound
Coefficient
Molar Mass
t
Cu(NO3)2(aq)
2
187.5558
Fe(CN)6(aq)
1
211.9494
Cu2Fe(CN)6(s)
1
339.0414
NO3(aq)
4
62.0049
Zn2Fe(CN)6
3 Zn + Fe(CN)6 = Zn3[Fe(CN)6]
Reaction type: synthesis
Reaction stoichiometry
Limiting reagent
Compound
Coefficient
Molar Mass
Moles
Weight
Zn
3
65.38
Fe(CN)6
1
211.9494
Zn3[Fe(CN)6]
1
408.0894
Reaction stoichiometry
Compound
Coefficient
Molar Mass
AlCl3(aq)
1
133.3405386
NaOH(aq)
3
39.99710928
NaCl(aq)
3
58.44276928
Al(OH)3(s)
1
78.0035586
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