t/takeCovalentActivity do?locator assignment-take Use the References to access i
ID: 1061433 • Letter: T
Question
t/takeCovalentActivity do?locator assignment-take Use the References to access important values if needed for this question. The vapor pressure of liquid acetone,CHscoCHa, is 100 mm Hg at 281 K AS32x10 g sample of liquid CHscoCHs is placed in a closed, evacuated 390. mL container at a temperature of 281 K. Assuming that the temperature remains constant, will all of the liquid evaporate? What will de pressure in the container bewben equilibrium is reached? mm Hg Retry Entire Group 2 more group attempts remainingExplanation / Answer
Find Pressure if the sample was total gas:
PV = nRT
P = nRT/V
MW of acetone =58.08 g/mol
mol = mass/MW = (8.32*10^-2)/(58.08 ) = 0.001432
so
P = (0.001432)(0.082*281)/(390*10^-3) = 0.0846054 atm
change to mm Hg --> 0.0846054*760 = 64.30 mm Hg
since this is LOWER... this will remain as a GAS/VAPOR 100%
the pressure will be then 64.30 mm Hg in the container
Q2
Relate Pressures:
P1V1 = P2V2
508*62 = P2*386
P2 = 508*62/386 = 81.595 mm Hg
since it is still < vapor pressure
this will remain as vapor 100%
P =
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.