The equilibrium constant for the formation of calcium carbonate from the ions in

Question

The equilibrium constant for the formation of calcium carbonate from the ions in solution is 2.2 times 10^8 according to the reaction: Ca^2+ (aq) + CO_3^2- (aq) CaCO_3(s) What is the value of the equilibrium constant for the reverse of this reaction? the same, 2.2 times 10^8 -2.2 times 10^9 4.5 times 10^-9 4.5 times 10^9 2.2 times 10^-8 Increasing the temperature of an exothermic reaction results in no change in the quantities of reactants and products. fewer reactants and products. more reactants and fewer products. more reactants and products. more products and fewer reactants.

Explanation / Answer

15)
Kc(reverse) = 1/kc(forward)
= 1/(2.2*10^8)
= 4.5*10^-9
Answer: c

16)
increasing temperature favours endothermic reaction
since backward reaction is endothermic, backward reaction will be favoured
equilibrium will shift to reactant side
Answer: c

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