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Question

.mastering chemistry.com/myctitemview?assignmentProblemID 67273202 httpsellsession. signed in as Nailah Connell l c Chm 114 Fall 2016 Problem 20.69 13of 14 Problem 20.69 Part A A voltaic cel is constructed with two Zn -zn isthe anode of the cel? Porn Ch electrodes. The two oel oompartments have 2012bor 16 M and Izn2 10 102M O compartment with Zn l 16 Mis the anode compartment with Znaj 10 102M the anode My Answers give All-1B- Part B H 202 What is the standard emfof the oil? GB (M) Af 10 x 0.0 Electro by A Helle May 9, 20 My Answers Part C what is the onl emt for the concentrations given? Express your answer using two significant figures. My Answers gimnup

Explanation / Answer

concentration cell:
Zn is both oxidised and reduced

Zn2+(cathode) + Zn -----> Zn2+(anode) + Zn

E = Eo - 0.059/2 log {[Zn2+]anode / [Zn2+]cathode}
[Zn2+]anode < [Zn2+]cathode to make E positive

A)
anode will be the one with lower concentration
compartment with [Zn2+] = 1.10*10^-2 M is the anode

B)
Eo cell = Eo cathode - Eo anode = 0
Answer: 0 V

C)
E = Eo - 0.059/2 log {[Zn2+]anode / [Zn2+]cathode}
= 0 - 0.059/2 log (1.10*10^-2 / 1.6)
= 0.064 V
Answer: 0.064 V

D)
At anode Zn2+ will increase

E)
At cathode Zn2+ will decrease