The vapor pressure of water at 21 degree C is 19 mmHg. If 100 ml of oxygen is co

Question

The vapor pressure of water at 21 degree C is 19 mmHg. If 100 ml of oxygen is collected over water at 21 degree C and 730 mmHg total pressure how much pressure is due to water vapor and how much to the pressure of oxygen? Write. chemical equation for the decompose by heat of potassium chlorate to from oxygen and potassium chloride. Will the addition of a small amount of manganese dioxide to the potassium chlorate change the above chemical reaction? Explain. A 2.05 g mixture of potassium chlorate and potassium chloride, upon heating liberated 425 ml of oxygen. This was collected over water at 21 degree C and 745 mmHg total pressure. What percentage of pure potassium chlorate was contained in the 2.05 g of mixture? Base your calculations on mole relationships.

Explanation / Answer

Q6

V = 100 mL

T = 21°C = 21+273 = 294 K

Ptotal = 730 mm Hg

Ptotal = Pgas + Pvapor

Pgas = Ptotal - Pvap = 730-19 = 711

so

a) pressure due to water vapor --> 19 mm Hg

b) pressure due to oxygen = 711 mm Hg

Q7

decomposition of KClO3

KClO3(s) + Heat --> KCl(s) + O2(g)

Q8

MnO2 + KClO3 --->

most likely it will oxidize it

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