use the following enthalpies of formation for Na2CO3.10H2O (s) -> Na2CO3(aq) +10

Question

use the following enthalpies of formation for Na2CO3.10H2O (s) -> Na2CO3(aq) +10H2O

you dont need to do the erro %. I just need the therotical value. thanks in advanc.

X co ther U223 Use the following enth of formation to calculate the theoretical values for the enthalpy of dissolution for CaCl and Nazcom 10Hzo. Calculate the percent error (for each experiment with the experimental data in Table 4.3. Species AHmo (kJ/mol) CaCl2 (aq) 877.13 CaCl2 (s) 795.8 Na,CO, (aq) -1157.34 4081.3 Na2CO3 10H20 (s) lase 1130.7 Na,CO, (s) Call 1- 57.34 thorar ae mor

Explanation / Answer

Na2CO3.10H2O(s) ----------> Na2CO3(s) + 10H2O (l)

Given-

Hf0 Na2CO3.10H2O = - 4081.3 KJ/mol

Hf0 Na2CO3 (s) = -1130.7 KJ/mol

Hf0 H2O = -286 KJ/mol

Add the heat of formations of the products and subtract from it the sum of the heat of formation for the reactants

Hr0 = -1130.7 KJ/mol + 10 (-286 KJ/mol) – (-4081.3 KJ/mol)

         = -1130.7 KJ/mol + (-2860 KJ/mol) – (- 4081.3 KJ/mol)

         = - 3990.7 + 4081.3 = 83.6 KJ/mol

Enthalpy for dissolution for Na2CO3.10H2O is 83.6 KJ/mol

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