1. What is the strongest reducing agent? Na F^- Fe^2+ Cd Fe^3+ 2. Balance the fo
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Question
1. What is the strongest reducing agent? Na F^- Fe^2+ Cd Fe^3+2. Balance the follow redox rxn. what are the coefficients in front of Cr & Cl2 in the balanced rxn?
Cr (s) + Cl2 (g) = Cr^3+ (aq) + Cl^- (aq)
3. Balance the follow redox rxn. what are the coefficients in front of Fe & Ag^+ in the balanced rxn?
Fe (s) + Ag^+ (aq) = Ag (s) + Fe^2+ (aq)
4. Balance the following redox rxn. What are the coefficients in front of Pb and H+?
Pb ^2+ (aq) + NH4 + (aq) = Pb (s) + NO3 - (aq) 1. What is the strongest reducing agent? Na F^- Fe^2+ Cd Fe^3+
2. Balance the follow redox rxn. what are the coefficients in front of Cr & Cl2 in the balanced rxn?
Cr (s) + Cl2 (g) = Cr^3+ (aq) + Cl^- (aq)
3. Balance the follow redox rxn. what are the coefficients in front of Fe & Ag^+ in the balanced rxn?
Fe (s) + Ag^+ (aq) = Ag (s) + Fe^2+ (aq)
4. Balance the following redox rxn. What are the coefficients in front of Pb and H+?
Pb ^2+ (aq) + NH4 + (aq) = Pb (s) + NO3 - (aq) Na F^- Fe^2+ Cd Fe^3+
2. Balance the follow redox rxn. what are the coefficients in front of Cr & Cl2 in the balanced rxn?
Cr (s) + Cl2 (g) = Cr^3+ (aq) + Cl^- (aq)
3. Balance the follow redox rxn. what are the coefficients in front of Fe & Ag^+ in the balanced rxn?
Fe (s) + Ag^+ (aq) = Ag (s) + Fe^2+ (aq)
4. Balance the following redox rxn. What are the coefficients in front of Pb and H+?
Pb ^2+ (aq) + NH4 + (aq) = Pb (s) + NO3 - (aq)
Explanation / Answer
The strengths of oxidizing and reducing agents are indicated by their standard electrode potentials.
Refer to standard electrode potentials,
In the given ions or elements Fe+2 is having highest standard electrode potential(negative sign shows it is favourable)
If Na was given in ionic form as Na+ could have been strongest , but it is given Na.
2. Cr + Cl2 ==> Cr+3+ Cl-
Cr ==> Cr+3 + 3e
Cl2+ 2e ==> Cl-
for balancing redox reaction we have to balance electrons in reactant and product in both oxidation and reduction half reactions.
We use cris-cross method generally
Hence, 3Cr + 2Cl2 ==> 3Cr+3 + 6Cl-
coefficients are 3,2
3. Ag++ e ==>Ag
Fe ==> Fe+2 + 2e
Here, by Cris-cross
Fe+2Ag+ ==> 2Ag + Fe+2
coefficient are 1,2
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