An insulated container is used to hold 46.00 g of water at 30.00 degree C. A sam

Question

An insulated container is used to hold 46.00 g of water at 30.00 degree C. A sample of copper weighing 15.20 g is placed in a dry test tube and heated for 30 minutes in a boiling water bath at 100.10 degree C. The heated test tube is carefully removed from the water bath with laboratory tongs and inclined so that the copper slides into the water in the insulated container. Given that the specific heat of solid copper is 0.385 J/(g middot degree C), calculate the maximum temperature of the water in the insulated container after the copper metal is added.

Explanation / Answer

Q = m c T
Q = quantity of heat in joules (J)
m = mass of the substance acting as the environment in
grams (g)
c = specific heat capacity (4.19 for H2O) in J/(g oC)
T = change in temperature = Tfinal - Tinitial in oC

Heat lost by copper = heat gained by water

15.2 x 0.385 x (110.1 -Tf) = 46 x 4.19 x (Tf - 30)

644.3052 - 5.852 Tf = 192.74Tf - 5782.2

6426.505 = 198.592Tf

Tf = 32.36

Hence the final temperature is 32.36 oC

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