the reaction Cr(NH3)6^3+(aq)+3en(aq)=Cr(en)3^3+(aq)+6NH3(aq) where en represents

Question

the reaction Cr(NH3)6^3+(aq)+3en(aq)=Cr(en)3^3+(aq)+6NH3(aq) where en represents ethylenediamine, has a small value for the enthalpy change,deltaHrxn, yet the free energy change is very negative because

a. the reaction rate is fast

b. the entropy change is large and positive

c. the enthalpy change is large enough to matter

d. the entropy change is large and negative

e. ethylene diamine has amino groups that are stronger bases than ammonia

I know that the anwer is b, but can someone explain in simple terms, why it is b

Explanation / Answer

Cr(NH3)6^3+(aq)+3en(aq)------->Cr(en)3^3+(aq)+6NH3(aq)

The total number of moles of reactants is 1+3=4

The total number of moles of products is 1+6=7

We the reaction is going on the number of moles increases there by disorderness of the molecules increases,so entropy is positive & is large.

Therefore option (b) is correct

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