Write the correct cell reaction.. QUESTION 1 The following cell notation contain
ID: 1058142 • Letter: W
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Write the correct cell reaction.. QUESTION 1 The following cell notation contains two half-reactions. Which of the following statement/equation correcty describes the two half reactions? O anode: Fe2+(aq) e 3+, cathode: sn4+raq) +2e-,sn2+(aq) anode: Fe2+(aq-e- Fe3+(aqo; cathode: 2+, aq+2e- sn4+(aqo anode: Sn4+(aq)+2e- Sn2+(aq); cathode: Fe (aq) e- 3+ (aq); 3+ anode: Fe3+(aq) O anode: Pt e Fe3+(aq)+Fe2+(aq) cathode: 2+ (aq)+2e- Pt QUESTION 2 Based on the cell notation given in the last question, write the correct cell reaction? Fe3+(aq)+sn2+(aq) Fe2+(aq) sn4+(aq) O Fe2+(aq) sn4+(aq) Fe3+(aq) Sn2+(aq 2Fe3+(aq) sn2+(aq) 2Fe2+(aq) +sn4+(aq) 2Fe3+(aq) Sne (aq Fe2+(aq)+Fe3+(aq) sn4+(aq) +sn? (aq)Explanation / Answer
Q) 1) Reduction occurs at cathode and oxidation occurs at anode.
Fe^2+ loses and electron and is oxidized to Fe^3+ and Sn^4+ accepts two electrons and reduced to Sn^2+.
Hence option 1 is correct.
Balanced equation is
Q) 2) 2Fe^2+(aq) + Sn^4+(aq) -------> 2Fe^3+(aq) + Sn^2+(aq)
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