Part B - Use the data in(Figure 1) to calculate reaction rate in terms of B duri

Question

Part B - Use the data in(Figure 1) to calculate reaction rate in terms of B during the time period of 1.00 min to 3.50 min.

Part C

The reaction rates calculated above in terms of A and B during the same time period (1.00 min to 3.50 min) are Please Choosedifferent. the same.

Part D - For the generic reaction: A? B

The Rate Expression is written as: Reaction Rate=?1a?[A]?t=1b?[B]?t

Why is there a negative sign in the expression for reaction rate in terms of the reactant A?

Part E - What does a negative sign in any rate expression mean?

Select all that apply.

calculate and compare the average rate during different time periods

for the same reaction, A? B

Part F - Calculate the average rate between 3.50 – 7.00 min.

Part G - Calculate the average rate between 7.00 – 12.00 min.

Part H

The reaction rate Please Choose

increases

decreases

remains constant

shows no trend  as the reaction proceeds.

Part I - Suggest an explanation for this trend.

The substance is being consumed. The reaction is proceeding backward. The substance is a reactant. The rate of the reaction is decreasing. None of the above. Time (min) 0.00 1.00 3.50 7.00 12.00 Table 1 A B [A] M 0.050 0.040 0.030 0.020 0.010 [Bl M 0.00 0.010 0.020 0.030 0.040

Explanation / Answer

From the given data in the table

Part B : rate in terms of B

= (0.02 - 0.01)/(3.5 - 1)

= 0.004 M/s

Part C : rate for A and B are different between 1 and 3.5 min

Part D : As the reaction progresses, the concentration of reactant A reduces, thus we have a -ve sign in front of A.

Part E : The negative sign means,

The substance is being consumed

The substance is a reactant

Part F : Average rate between 3.50 - 7.00 min

= -(-0.01)/3.5

= 0.00286 M/min

Part G : average rate between 7-12 min

= -(-0.01)/5

= 0.002 M/min

Part H : The reaction rate

decreases

Part I : As the reaction progresses, the saturation point is reached due to accumulation of product in the system which lowers the rate of forward reaction.

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