Get answers for kai(so4)2 and 328 Report of sals and pH solatio\"\" the CHO, QUE

Question

Get answers for kai(so4)2 and 328 Report of sals and pH solatio"" the CHO, QUESTIONS Hydrolysis of Bamer 's for i. Using the K.'s calculate he p co, for IC,H,o, F. measured ions, compare these and Hco drom from your values with those calculated calcu- value with that this 2. ng As for x G), calculate the NH ion compare NH3 (from Appendi A, for lated from your measured pH's lution of KC2H302? that of 0.1 M a 3. How should the pH of a 0.1 M solution of NaC2Hyo2 compare with Explain briefly. 4. What is the greatest source of error in this experiment? How could minimize this source of error? you B. pH of Buffer Solutions Mass of NaC2H30, -3H,0 (Fw 36 gmol) 3 pH of original buffer solution pH of buffer HCl pH buffer NaoH Calculate pH of original buffer (show calculations) pyright c 2015 Pearson Education, Inc.

Explanation / Answer

1. Ka for HC2H3O2 = 1.8 x 10^-5

Kb for C2H3O2- = 1 x 10^-14/1.8 x 10^-5 = 5.55 x 10^-10

Ka for HCO3- = 4.8 x 10^-11

Kb for CO3^2- = 1 x 10^-14/4.8 x 10^-11 = 2.08 x 10^-4

2. Kb for NH3 = 1.8 x 10^-5

Ka for NH4+ = 1 x 10^-14/1.8 x 10^-5 = 5.55 x 10^-10

3. pH for both NaC2H3O2 and KC2H3O2 would be the same as they both give the same ion C2H3O2- in solution which hydrolyzes to form OH-.

4. The major source of error could be from incorect measurement of volume of solution. The volumes and thus exact molarity of solution can be known by standarizing it against a solution of known concentration.

Solution

NaC2H3O2

hydrolysis : C2H3O2- + H2O <==> HC2H3O2 + OH-

Kb = [HC2H3O2][OH-]/[C2H3O2-] = 5.55 x 10^-10

Na2CO3

hydrolysis : CO3^2- + H2O <==> HCO3- + OH-

Kb = [HCO3-][OH-]/[CO3^2-] = 2.08 x 10^-4

NH4Cl

hydrolysis : NH4+ + H2O <==> NH3 + H3O+

Ka = [NH3][H3O+]/[NH4+] = 5.55 x 10^-10

ZnCl2

hydrolysis : H+ + OH- <==> H2O

Kw = [H+][OH-] = 1 x 10^-14

KAl(SO4)2

hydrolysis : Al3+ + 3H2O <==> Al(OH)3 + 3H+

Keq = [Al(OH)3][H+]^3/[Al3+] = 1.3 x 10^-33

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