This is a LIQUID CHROMATROGRAPHY question.. i am stuck in this question. PLEASE

Question

This is a LIQUID CHROMATROGRAPHY question.. i am stuck in this question. PLEASE HELP! I would look forward to give a good rating if the answers are correct.

(PLEASE DONT FORGET TO ANSWER IN AS MUCH DETAIL AS POSSIBLE. I NEED TO UNDERSTAND)

roblenm Problem 1: Albuterol (a drug used to fight asthma) has a lipid:water K value of 0.019. How many grams of albuterol would remain in the aqueous phase if 0.001 grams of albuterol initially in a 100 mL aqueous solution were allowed to come into equilibrium with 100 mL of octanol? 12

Explanation / Answer

Kow is defined as the [concentration of albuterol in octanol]/[concentration of albuterol in water].

Therefore, by subsituting the values,

The concentration of albuterol in octanol would be: 0.01 * 0.019 = 0.000019

Therefore, the remaining amount of albuterol present in the aqueous phase would be 0.01- 0.000019 = 0.0009981g

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