Write the balanced neutralization reaction between H2SO4 and KOH in aqueous solu

Question

Write the balanced neutralization reaction between H2SO4 and KOH in aqueous solution. Phases are optional.

0.450 L of 0.450 M H2SO4 is mixed with 0.400 L of 0.260 M KOH. What concentration of sulfuric acid remains after neutralization?

Map dot Sapling Learning mactliah learming Write the balanced neutralization reaction between H2S04 and KOH in aqueous solution Phases are optional. 0.450 L of 0.450 M H2SO4 is mixed with 0.400 L of 0.260 M KOH. What concentration of sulfuric acid remains after neutralization? Number M H,SO

Explanation / Answer

H2SO4 + 2KOH -------------> K2SO4 + 2H2O

moles of KOH added = 0.26 x 0.4 = 0.104

0.104 / 2 = 0.052 moles H2SO4 neutralize.

moles of H2SO4 left = (0.45 x 0.45) - 0.052 = 0.1505 moles H2SO4 left

total volume = 0.4 + 0.45 = 0.85 L

[H2SO4] = 0.1505 / 0.85 = 0.177 M

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