b=23.2 c=21.3 d=99.5 e=27.5 f=27.5-21.3=6.2 ?? g=99.5-27.5=72 ?? Are answer of f

Question

b=23.2

c=21.3

d=99.5

e=27.5

f=27.5-21.3=6.2 ??

g=99.5-27.5=72 ??

Are answer of f and g correct?

3. The specific heat of the metal was determined following a procedure similar to part A of lab procedure. Complete the following table using the data given. A 35.3g sample of metal beads was heated in a water bath and the temperature of the water bath was 99.5°C. The metal was then added to a sample of water (23.2g) and the temperature of the water changed from an initial temperature of 21.3°C to a maximum temperature of 27.5°C gained from plotted graph. a. Mass of metal: b. Mass of water: c. Initial temperature of water in calorimeter (T of water): d. Initial temperature of metal (boiling water) (T,of metal): e. Maximum temperature of metal and water mixture (°C): f. T ): of water (°C Show calculation: of metal (°C): Show calculation: g·

Explanation / Answer

Mass of the metal = 35.3 g

Mass of water = 23.2 g

Initial temperature of water = 21.30C

Initial temperature of a metal = 99.50C

Maximum temperature = 27.50C

delta T (water) = 27.5-21.3 = 6.20C

delta T(metal) = 99.5-27.5 = 720C

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