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Suppose that the reaction: C rightarrow products is second order in C and has a

ID: 1055468 • Letter: S

Question

Suppose that the reaction: C rightarrow products is second order in C and has a rate constant k = 4.77 times 10^-2 M^-1 min^-1. First write the rate equation (rate law), and then answer the following question. At what [C] will the rate equal 3.99 times 10^-3 M min^-1? 0.289 M 0.0837 M 12.0 M 3.46 M 0.403 M Suppose the following data are for the reaction: A rightarrow products If the reaction is second order in A, calculate the value of the rate constant k. 0.086 M^-1 hr^-1 0.14 M^-1 hr^-1 0.33 M^-1 hr^-1 0.054 M^-1 hr^-1 6.2 M^-1 hr^-1

Explanation / Answer

22)
rate = k [C]^2
3.99*10^-3 = 4.77*10^-2 [C]^2
[C] = 0.289 M
Answer: a

23)
integrated rate law for second order reaction
1/[A] = 1/[A]o + k*t
1/0.568 = 1/(0.675) + k*2
k = 0.14 M-1hr-1
Answer: b

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