In Lab 11 you make a stock solution of salicylic acid, and then four dilutions.

Question

In Lab 11 you make a stock solution of salicylic acid, and then four dilutions. The stock solution is made by diluting 10.00 ml of 1.250 times 10^-2 M salicylic acid in 100.00 ml of solution. You then make the four dilutions as follows: Dilution #1 = 40.00 mL of stock diluted to 100.00 ml Dilution #2 = 30.00 ml of stock diluted to 100.00 mL Dilution #3 = 20.00 ml of stock diluted to 100.00 ml Dilution #4 = 10.00 mL of stock diluted to 100.00 mL Determine the concentrations of the stock solution and four dilutions and enter them in the tables below.

Explanation / Answer

10.00mL of 1.250x10-2 M of Salicylic acid

moles = 0.01 L x 1.250x10-2 M = 1.25 x 10-4 mol

Volume = 100 mL = 0.1L

M = 1.25x10-4 mol/0.1L = 1.25 x10-5 M

Stock Solution: 1.25 x10-5 M

Dilution 1: 40.00 mL of stock solution diluted to 100 mL

M1V1 = M2V2

0.040L x  1.25 x10-5 M / M2 x 0.1L

M2 = 0.5 x 10-5 M

Dilution 2: 30.00 mL of stock solution diluted to 100 mL

M1V1 = M2V2

0.030L x  1.25 x10-5 M / M2 x 0.1L

M2 = 0.375 x 10-5 M

Dilution 3: 20.00 mL of stock solution diluted to 100 mL

M1V1 = M2V2

0.020L x  1.25 x10-5 M / M2 x 0.1L

M2 =0.25 x 10-5 M

Dilution 4: 10.00 mL of stock solution diluted to 100 mL

M1V1 = M2V2

0.010L x  1.25 x10-5 M / M2 x 0.1L

M2 = 0.125 x 10-5 M

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