So these are the formulas ... where does Q come from and where does K come from

Question

So these are the formulas ... where does Q come from and where does K come from ??? For a particular reaction, 27.58 kJ/mol and AS-284.6 J/(mol-K). Calculate for this reaction at 298 K Number kJ/mol What can be said about the spontaneity of the reaction at 298 K? O O O The system is at equilibrium. The system is spontaneous in the reverse direction. The system is spontaneous as written Hint O Previous G ve Up & View Sotton Check Answer 0 Next y attention to units and make any necessary conversions. Notice that the enthalpy change is given in units of ojoules per mole; whereas, the entropy change is given in joules per mole times kelvin. You'll need to do a conversion such that the energy units match

Explanation / Answer

We know that;

G = H- T S

G= Gibbs Free Energy    H = Enthalpy 27.58 KJ/mole

   T = temperature in Kelvin ;298 K

S = Entropy 284.6 J/ mole –K

Therefore ;

G = H- T S

G = 27.58 KJ/mole *1000 J/1.0 KJ – 298 K * 284.6 J/ mole –K

G =27580 J/mole – 84840.8 J/ mole

= - 57230.8 J/ mole

= - 57.2308K J/ mole

G < 0 , the reaction is spontaneous
G > 0, the reaction is nonspontaneous
G = 0, the reaction is at equilibrium

Here G is negative means G < 0 , then the reaction is spontaneous

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