HM II 27 CHM 112 Experiment 7-Laboratory Report Sheets of NaOH Solution Tha Tria

Question

HM II 27 CHM 112 Experiment 7-Laboratory Report Sheets of NaOH Solution Tha Trial 3 Trial 1 Trial 2 HCl buret 25. buret 5 m 5.00 mL 40.06 mL (m eading NaOH buret B Determination of the Molar Mass of an Unknown Acid Unknows kter Mass af vial plus contents Mass af val plus contents less sample 1 Mass ofvial plus contents less sample2 16.4 0.07 8 9 7241 Trial 1 Trial 2 Initial reading, NaOH buret Final reding NaOH buret Initial reaing H buret Final redin, Ha buret mL mL O. 60 0.o m mL mL mL mL 0.00 mL

Explanation / Answer

Determination of molar mass of unknown acid

Mass of sample 1 = 0.4 g

Mass of sample 2 = 0.6959 g

Volume of NaOH used = 31.01 ml (trial 1)

moles of NaOH used = 0.09983 M x 31.01 ml = 3.096 mmol

Volume of HCl used = 0

moles of HCl used = 0

moles of unknown acid = 3.096 mmol

molar mass of unknown acid = 0.4 g/0.003096 mol = 129.20 g/mol (Trial 1)

molar mass of unknown acid = 0.6959 g/0.09983 M x 0.02303 l = 302.56 g/mol (Trial 2)

Average molar mass of unknown acid = 215.88 g/mol

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