the titration of a 50.00 ml sample of fresh fruit juice required 26.80 ml of iod

Question

the titration of a 50.00 ml sample of fresh fruit juice required 26.80 ml of iodine solution to reach the blue endpoint. 1.00 ml of the iodine solution is equivalent to 1.14 mg of vitamin C. how many milligrams of vitamin C are in each 1.00 ml of the fruit juice? the titration of a 50.00 ml sample of fresh fruit juice required 26.80 ml of iodine solution to reach the blue endpoint. 1.00 ml of the iodine solution is equivalent to 1.14 mg of vitamin C. how many milligrams of vitamin C are in each 1.00 ml of the fruit juice? the titration of a 50.00 ml sample of fresh fruit juice required 26.80 ml of iodine solution to reach the blue endpoint. 1.00 ml of the iodine solution is equivalent to 1.14 mg of vitamin C. how many milligrams of vitamin C are in each 1.00 ml of the fruit juice?

Explanation / Answer

1 ml of iodine = 1.14 mg of Vit C

so...

if we required 26.8 mL of Iodine...

this is...

mass of Vitamin C = 26.8 mL * 1.14 mg Vit C / mL iodine = 30.552 mg of Vitamin C

this is in a 50 mL sample

we require in 1 mL

so..

1/50*30.552 =

(1 / 50) * 30.55200 =

0.61104 mg of Vitamin C per mL of juice

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