if it required 14.70 ml of iodine to titrate 50.00 ml of \"practice vitamin C\"

Question

if it required 14.70 ml of iodine to titrate 50.00 ml of "practice vitamin C" solution, how many milligrams of vitamin C is present in each 1.00 ml of practice solution? 1.00 ml of iodine solution is equivalent to 1.07 mg of vitamin C. if it required 14.70 ml of iodine to titrate 50.00 ml of "practice vitamin C" solution, how many milligrams of vitamin C is present in each 1.00 ml of practice solution? 1.00 ml of iodine solution is equivalent to 1.07 mg of vitamin C. if it required 14.70 ml of iodine to titrate 50.00 ml of "practice vitamin C" solution, how many milligrams of vitamin C is present in each 1.00 ml of practice solution? 1.00 ml of iodine solution is equivalent to 1.07 mg of vitamin C.

Explanation / Answer

V = 14.7 mL of Iodin

V = 50 mL of Vitamine C

find mg of C

1 mL of solution....

note that 1 mL of iodine --> 1.07 mg of Vit C....

so;

14.7 mL --> 14.7 / 1 * 1.07 = 15.729 mg of Vitamin C

this was present in 50 mL of vitaminc C

so... for 1 mL

50 mL vit C = 15.729 mg

1 mL --> 1/50 * 15.729 = 0.31458 mg of Vitamin C in 1 mL of mix

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