No two electrons can have the same four quantum numbers is known as the Pauli ex

Question

No two electrons can have the same four quantum numbers is known as the Pauli exclusion principle Hund's rule Aufbau principle Heisenberg uncertainty principle Give the set of four quantum numbers that could represent the last electron added (using the Aufbau principle) to the Ne atom. n = 3, l = 1, m_1 = 1, m_s = + 1/2 n = 3, l = 0, m_l = 1, m_s = - 1/2 n = 3, l = 2, m_l = 1, m_s = + 1/2 n = 2, l = 1, m_l = 1, m_s = - 1/2 n = 3, l = 2, m_l = 1, m_s = - 1/2 Give the number of valence electrons for O. 0 2 4 6 8 The element that corresponds to the electron configuration 1s^2 2s^2 2p^6 is ___. Sodium magnesium lithium beryllium neon The complete electron configuration of gallium, element 31, is 1s^2 2s^2 2p^10 3s^2 1s^2 2s^2 2p^10 3s^2 3p^10 4s^2 3d^3 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^1 1s^4 2s^4 2p^6 3s^4 3p^6 4s^4 3d^3 1s^4 2s^4 2p^10 3s^4 3p^9 1s^4 2s^4 2p^8 3s^4 3p^8 4s^3 The condensed electron configuration of krypton, element 36, is ___. [Kr]4s^2 3d^8 [Ar]4s^4 [Kr]4s^4 3d^8 [Ar]4s^2 3d^10 4p^6 [Ar]4s^4 3d^4 Give the ground state electron configuration for Se. [Ar]4s^2 3d^10 4p^4 [Ar]4s^2 4d^10 4p^4 [Ar]4s^2 3d^10 4p^6 [Ar]4s^2 3d^10 [Ar]3d^10 4p^4 Which of the following have their valence electrons in the same shell? Li, N, F B, Si, As N, As, Bi He, Ne, F How many unpaired electrons are present in the ground state P atom? 0 3 1 2 4 Place the following elements in order of decreasing atomic radius. Xe Rb Ar Ar > Xe > Rb Xe > Rb > Ar Ar > Rb > Xe Rb > Xe > Ar Rb > Ar > Xe Of the following, which atom has the largest atomic radius? Rb l Cs Al Place the following in order of increasing IE.: N F As N

Explanation / Answer

Q1.

This is Pauli Exlcusion principle, exclues the SAME value for each electron, so they cannot occupy the same "position"

Q2.

last electron of Neon:

electronic configuration = 1s2 2s2 2p6

then, last must be ---> n = 2; p stands for l = 1 , ml =0, +1/-1; ms = +1/2 and -1/2

ignore A, B C and E, since n = 3 whhich cant be

so this is D

Q3

Oxygen is in family VIA, meaning ti has 6 electrons in its valence

Q4

total electorn count = 2+2+6 = 10

Neon has 10 electrons, choose neon

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