ms/mod/ibis/view.php?id 271527 GINsystem EDUC articles 6 Gra 11/9/2016 11:55 PM

Question

ms/mod/ibis/view.php?id 271527 GINsystem EDUC articles 6 Gra 11/9/2016 11:55 PM 83.5loo 11/8/2016 04:27 PM Print Calculator B Periodic Table estion 18 of 23 Mapa Sapling earning Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(r)oxide: You add 345 g of Mnoh to a solution containing 46.3 g of HCI. (a) What is the limiting reactant? O Mnoz O HCI (b) What is the theoretical yield of Chi? (c) the yield of the reaction is 869% what is the actual yield of chlorine? o Previous ® Give up & view solution 2 Check Anewer o Next SExa

Explanation / Answer

a)

number of moles of MnO2 = mass/ molar mass
= 34.5 / 86.9
=0.397 mol

number of moles of HCl = mass/ molar mass
= 46.3 / 36.5
=1.27 mol

1 mol of MnO2 needs 4 mol of HCl to react completely
0.397 mol of MnO2 will need 4*0.397 = 1.588 mol of HCl
But we have just 1.27 mol of HCl

so, HCl is limiting reagent

b)
4 mol of HCl forms 1 mol of Cl2
moles of Cl2 formed = moles of HCl/4
= 1.27/4
=0.3175 mol

molar mas of Cl2 = 71 g/mol
mass of Cl2 = number of mol * molar mass
= 0.3175 mol * 71 g/mol
= 22.5 g Cl2
Answer: 22.5 g

c)
actual yield = 86.9 % of theoretical
= 86.9*22.5/100
= 19.6 g
Answer: 19.6 g

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