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/ibisvi e c Under standard conditions (29 Waiting for sap nazon.com-Online Sh Tr

ID: 1051661 • Letter: #

Question

/ibisvi e c Under standard conditions (29 Waiting for sap nazon.com-Online Sh TripAdvisor y Lecture IN- Ploidy and re... y Lecture IN- Ploidy and re- Print calculator Periodic Table uestion 7 of 28 Sapling Learning macmillan learning For a particular reaction, AH --14.20 kJ and AS 198.5 JK Calculate AG for this reaction at 298 K. Number kJ What can be said about the spontaneity of the reaction at 298 K? O The system is spontaneous in the reverse direction. O The system is spontaneous as written. O The system is at equilibrium.

Explanation / Answer

we know that

dG = dH - TdS

given that

dH = -14.2 x 1000 J

dS = -198.5 J/K

T = 298 K

so

using those values

we get

dG = (-14.2 x 1000) - (298 x -198.5)

dG = 44953 J

dG = 44.953 x 1000 J

dG = 44.953 kJ

we know that

if dG < O , the system is spotaneous in as written

if dG = 0 , the system is at equilibrium

if dG > 0 , the system is spontaneous in the reverse direction

in this case

dG > 0

so

the system is spontaneous in the reverse direction