One method that can increase the solubility of some salts is to form a soluble c

Question

One method that can increase the solubility of some salts is to form a soluble complex ion. Which statement best describes the reason behind this method's result? CuS has a K_sp of 8.5 times 10^-45. The reaction for Cu^2+(aq) + 4 NH_3(aq) rightarrow Cu(NH_3)_4^2+ has an equilibrium constant of approximately 5.6 times 10^11. What would be the approximate molar solubility of CuS in a 1.0 M solution of NH_3? ~ 6.9 times 10^-17 M ~ 9.2 times 10^-23 M ~ 4.8 times 10^-33 M This one seems too "complex".

Explanation / Answer

    CuS = Cu^2+ + S^2- ; Ksp = 8.5*10^-45

I---x--------0---------0

E-----------x----------x

Ksp = [Cu^2+][S^2-] = 8.5*10^-45

Ksp = x.x = 8.5*10^-45

x = sqrt(8.5*10^-45) = 9.2*10^-23 M

The molar solubility of CuS in 0.1 M solution of NH3 = 9.2*10^-23 M

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