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For which of the following systems at equilibrium and at constant temperature wi

ID: 1051569 • Letter: F

Question

For which of the following systems at equilibrium and at constant temperature will decrease the volume cause the equilibrium to shift to the righr? NH_4Cl(s) NH_2(g) + HCl(g) H_2(g) + Cl_2(g) 2HCl(g) 2H_2O(g) 2H_2(g) + O_2(g) 2NO_2(g) 2NO(g) + O_2(g) N_2(g) + 3H_2(g) 2NH_3(g) For which of following reaction are the numerical values of K_p and K the same? 2SO_2(g) + O_2(g) 2SO_2(g) N_2(g) + O_2(g) 2NO(g) H_2(g) + I_2(g) 2HI(g) 2 only 1, 2, and 3 2 and 3 only 1 only 1 and 2 only Consider the following equilibrium: C_2H_6(g) + C_5H_12 (g) CH_4(g) + C_6H_14(g); K_p = 9.57 at 500K. Suppose 11.9 g each of CH_4, C_2H_6, C_5H_12, and C_6_14 are placed in a 50.0-L reaction vessel at 500 K. What is the value of Q_p? 0.104 0.637 1.00 9.57 1.57 Nitric oxide reacts with hydrogen at a measurable rate at 1000 K according to the following equation: 2NO + 2H_2 rightarrow N_2 + 2H_2O The experimental rate taw is Rate = k[NO]^2[H_2]. If time is measured in minutes and concentration is measured in moles per liter, what are the units for the rate of production of nitrogen. mol^2/(L^2 middot min). mol^3/(L^3 middot min). mol/(L^2 middot min). L^2/(mol^2 middot min). mol/(L middot min). Which of the following corresponds to the correct integrated expression for a first-order reaction? 1/A - 1/A_0 = kt 1/A_0 - ln A/A_0 = kt ln A - ln A_0 = -kt t_1/2 = 0.693/k 1/A - 1/B = kt At a given temperature, a first-order reaction has a rate constant of 2.0 times 10^-3 s^-1. How long will it take for the reaction to be 33% complete? 1700 s 550 s 87 s 2100 s 200 s In a first-order reaction, the half-life is 125 minutes. What is the rate constant? 5200 s^-1 0.333 s^-1 1.33 times 10^-4 s^-1 5 54 times 10^-3 s^-1 9.24 times 10^-5 s^-1

Explanation / Answer

32)
decreasing volume will move the reaction where there are less gaseous molecules
Only E has lesser number of molecules on product side as compare to that on reactant side
hence Answer is E

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