What element forms a 3+ cation whose configuration ends in 4d^6? The answer is r

Question

What element forms a 3+ cation whose configuration ends in 4d^6?
The answer is rhodium but how? Isn't the 4d^6 in period 4?such as iron? I'm missing something, obviously. Very Confused.. thanks What element forms a 3+ cation whose configuration ends in 4d^6?
The answer is rhodium but how? Isn't the 4d^6 in period 4?such as iron? I'm missing something, obviously. Very Confused.. thanks
The answer is rhodium but how? Isn't the 4d^6 in period 4?such as iron? I'm missing something, obviously. Very Confused.. thanks

Explanation / Answer

Rh(III) is [Kr]4d6 where [Kr] is the electron configuration of the closed shell element krypton.

The atomic state of Rh(0) is [Kr] 5s2 4d7 but it is the 5s2 electrons that are lost first when Rh(III) is formed

In the Fe(0) state (the neutral metal atom) the configuration is [Ar] 3d6 4s2

In Fe(3+) state, the electron configuration is Fe3+[Kr]3d5

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