Homework #16 Problem 16.67 Resources « previous | 3 of 10 |next » Part A Problem

Question

Homework #16 Problem 16.67 Resources « previous | 3 of 10 |next » Part A Problem 16.67 Calculate ASS at 1055 K surr For the melting of sodium chloride, usion-28.16 kJ/mol and Anson-26.22 J/ (K . mol Express your answer using two decimal places. assurr= 26.69 Submit My Answers Give Up Incorrect; Try Again; 5 attempts remaining Part B Calculate Stotal at 1055 K Express your answer using two decimal places. AZO J/(K) Submit My Answers Give Up Part C Calculate Ssurr at 1074 K Express your answer using two decimal places. ASsurr = 26.22

Explanation / Answer

at 1055 K, entroy change of surrounidings= enthalpy change/ temperature = 28.16*1000/1055=26.69

Entropy of system + entropy of surrounidings = total entropy change =0

entropy of surroundings = - entropy of surroundings = -26.69 J/mole

2. at 1074 K, entropy change = 28.16*1000/1074= 26.62 J/mole, entorpy change of surrounidings=-26.22 j/mol

3. at 1100K, entropy change= 28.16*1000/1100= 25.6 J/mole, entropy change of surroundings= -25.6 k/mole

at meltirng point, deltaH= TdeltaS, T= 28.16*1000/26.22= 1074K, melting point of NaCl.

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