please help me with an answer for the last question in this thread, and provide
ID: 105019 • Letter: P
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please help me with an answer for the last question in this thread, and provide a short reason why
What is meant by the term "limiting reagent" or a chemical reaction. Provide a few specific examples please answer the last question in this thread "What substance is the limiting reagent during this process" prove a short explanation Words: 17 Re: Chapter 4 DQ posted by Dec 05, 2017, 9:25 PM Chapter 4 describes limiting reactants as a substance in a reaction that is completely utilized in the reaction (Openstax 202). There are no leftovers. After this substance is totally consumed, the reaction must be complete. It cannot continue without it. One example used is sandwiches, with varying amounts of bread and cheese. If you were to have 14 pieces of cheese and 34 pieces of bread, you can make 14 sandwiches, which 6 leftover pieces of bread. Leftover reactants are referred to as excess reactants. To put it simply, it is a ratio of one reactant to another. Another example could be a reaction that utilizes 5 mol of Nitrogen for every 7 mol of Oxygen. This would provide a ratio of 5:7 meaning that one will be in excess and the other a limiting reactant. In this scenario, Nitrogen would be the limiting reactant and Oxygen would be the excess reactant. Words: 143 Re: Chapter 4 - DQ2 posted by . . . I , Dec 10, 2017, 11:51 AM Therefore, quite often one reactant will be present in excess It's a good analogy, often huge excess. If you have a gas-powered cook top you burn natural gas (mainly methane) to generate the heat. Which substance is the limiting reagent during this process?Explanation / Answer
Limiting reagent is the one which is smaller quantities and completely consumed in the reaction in the presence of other reactant which won't consume completely in the reaction (excess in quantity)
Ex: Combustion of methane in the presence of excess oxygen. Methane consumed completely and forms CO2 & H2O.
CH4 (g) + 2 O2 (g) = CO2 (g) + 2 H2O (l)
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