16. What is the empirical formula for the ionic crystal structure pict the right

Question

16. What is the empirical formula for the ionic crystal structure pict the right? For clarity each atomis labeled as b-body, face, e-edge and c corner. A) A2B B) AB2 C) AB2 E) AB In a body-centered cubic unit cell there areatoms per unit cell and each atom has a coordination number of A) 4, 12 B) 2,8 C) 4, 8 D) 4,6 E) 2, 6 18. [6 points] Platinum has an atomic radius of 0.139 nm. The density of platinum is 21.45 g/cm. What is the crystal structure of platinum? A) simple cubic B) face centered cubic C) body centered cubic D) More than one cubic crystal structure is possible. E) Unable to determine using the information provided.

Explanation / Answer

16. From given pictures we can see that 4 anion are present at face centre and 2 at body so B:-4×1/2+2=4

Cations are present at corners as well as at body centre

So A= 8×1/8+1=2

A:B=2:4

So formula would be A2B4

Answer:-D

17. In body centre cubic particles are present at corners as well as at body centre. So number of particles per unit cell is 2 and coordination number is 8.

Answer:-B

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